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Example: To improve a 3-phase, 40hp induction motor operating at 460v., 42 amps and .87
power factor to .95 power factor:Actual power=(460vx42ampsx.87P.F.x1.732)/1000 = 29.1 KW
Necessary reactive component=Actual PowerxFactor (from table)=29.1x.238=6.9 KVAR<

 
Power Factor Correction KVAR (Kilo Volt Amps Reactive)
Orig. P.F.% Desired P.F.%
80 85 90 95
60 .583 .713 .849 1.004
62 .516 .646 .782 .937
64 .451 .581 .717 .872
66 .388 .518 .654 .809
68 .328 .458 .594 .749
70 .270 .400 .536 .691
72 .214 .344 .480 .635
74 .159 .289 .425 .580
76 .105 .235 .371 .526
77 .079 .209 .345 .500
78 .052 .182 .318 .473
79 .026 .156 .292 .447
80 .130 .266 .421
81 .104 .240 .395
82 .078 .214 .369
83 .052 .188 .343
84 .026 .162 .317
85 .136 .291
86 .109 .264
87 .083 .238
88 .056 .211
89 .028 .183
90 .155
91 .127
92 .097
93 .066
94 .034
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